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Find the error...JPA ENTITY HIBERNATE

.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax ... static final long serialVersionUID = 1L; // @GeneratedValue @Id @Column(name = "id") @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; @Column(name = "username") private

Problem with entities detection

.persistence.Basic; import javax.persistence.Column; import javax.persistence.Embedded; import javax ... ) @Column(name = "id_alumno") private Long idAlumno; @Column(name = "dni") private String dni; @Column(name = "nombre") private String nombre; @Column(name = "apellidos

Relationships and tracking changes

Serializable { private static final long serialVersionUID = 1L; @Id @Column(name = "ID ... Serializable{ private static final long serialVersionUID = 1L; @Id @Column(name = "ID") @GeneratedValue(strategy = GenerationType.AUTO) private Long id; @ManyToOne @Column(name = "VERLAG_ID

JoinColumn.nullable

class="description"> (Optional) Whether the foreign key column is nullable.

SecondaryTable.uniqueConstraints

addition to any constraints specified by the Column and JoinColumn

GenerationType.IDENTITY

that the persistence provider must assign primary keys for the entity using a database identity column.

MapKeyJoinColumn.updatable

> (Optional) Whether the column is included in SQL UPDATE

ColumnResult.name

class="description"> (Required) The name of a column in the SELECT clause of a SQL query

javax.persistence.OneToOne

that maps a foreign key column // On Customer class

Embedded.nullIndicatorValue

The value in the null column to interpret the object