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1-27 of 27 resultsJPA Metamodel API); // Get an entity type: EntityType type2 = metamodel. entity (MyEntity.class);   ... - represents user defined mapped super classes. EntityType - represents user defined ... = entityType . getSupertype (); // Checks if the type has a single ID attribute: boolean hasSingleId | |
EntityManagerFactory.getNamedEntityGraphs(entityType) - JPA Method JPA Method in jakarta.persistence.EntityManagerFactory Map getNamedEntityGraphs ( Class entityType ) A map keyed by plain, containing every named plain whose entity type is assignable to the given Java type. Parameters: entityType - any Java type, including {@code Object.class | |
InterfaceRef jakarta.persistence.metamodel.EntityType JPA Interface EntityType Type Parameters: - The represented entity type. Super Interfaces: Bindable , IdentifiableType , ManagedType , Type An instance of EntityType represents an plain type. Since: JPA 2.0 Public Methods SingularAttribute getDeclaredId (Class type) Return the attribute | |
EntityType.getName() - JPA Method JPA Method in jakarta.persistence.metamodel. EntityType String getName () Return the entity name. Return: entity name Since: JPA 2.0 | |
EntityManager getMetamodel() causes crash(" EntityType : " +e.getName())); : ObjectDB returns with: Exception in thread "main" com.objectdb.o ... -one, Eg: Metamodel m = em.getMetamodel(); EntityType Point_ = m.entity(Point.class);   ... ().getEntities().forEach((e) - System.out.println(" EntityType : " +e.getName())); em.close(); emf.close | |
InterfaceRef jakarta.persistence.criteria.CriteriaDelete 2.1 Root from ( EntityType entity) Create and add a query root corresponding to the entity ... ( EntityType type) Create a subquery of the query. Parameters: type - the subquery result type | |
InterfaceRef jakarta.persistence.metamodel.Metamodel an embeddable class Since: JPA 2.0 EntityType entity (Class cls) Return the metamodel entity type ... entity type Throws: IllegalArgumentException - if not an entity Since: JPA 2.0 EntityType entity | |
InterfaceRef jakarta.persistence.EntityManagerFactory of the persistence unit. Since: JPA 3.2 Map getNamedEntityGraphs (Class entityType ) A map keyed by plain ... : entityType - any Java type, including {@code Object.class} meaning all entity graphs - the specified | |
InterfaceRef jakarta.persistence.criteria.From - target of the join jt - join type Return: the resulting join Since: JPA 2.0 Join join ( EntityType ... representing the join target Return: the resulting join Since: JPA 3.2 Join join ( EntityType   | |
InterfaceRef jakarta.persistence.criteria.AbstractQuery class Return: query root corresponding to the given entity Since: JPA 2.0 Root from ( EntityType ... ( EntityType type) Create a subquery of the query. Parameters: type - the subquery result type | |
InterfaceRef jakarta.persistence.criteria.Join Since: JPA 2.0 Join join ( EntityType entity) Create and add an inner join to the given entity ... Inherited from: From Since: JPA 3.2 Join join ( EntityType entity, JoinType joinType | |
InterfaceRef jakarta.persistence.criteria.CriteriaUpdate to the given entity Since: JPA 2.1 Root from ( EntityType entity) Create and add a query root ... Subquery subquery ( EntityType type) Create a subquery of the query. Parameters: type | |
Duplicate Entity class names causes Exception in Query I tried adding an explicit inspection of the EntityType using the metamodel public IMapItem getMapItem(Integer cachedKey, EntityManager em) { Metamodel metamodel = em.getMetamodel(); EntityType | |
Metamodel.entity(cls) - JPA Method JPA Method in jakarta.persistence.metamodel.Metamodel EntityType entity ( Class cls ) Return the metamodel entity type representing the entity. Parameters: cls - the type of the represented entity Return: the metamodel entity type Throws: IllegalArgumentException - if not an entity Since: JPA 2.0 | |
InterfaceRef jakarta.persistence.criteria.Root JPA Interface Root Type Parameters: - the entity type referenced by the root Super Interfaces: FetchParent , From A root type in the from clause. Query roots always reference entities. Since: JPA 2.0 The FROM clause (JPQL / Criteria API) article explains how to use Root . Public Methods EntityType | |
Root.getModel() - JPA Method JPA Method in jakarta.persistence.criteria.Root EntityType getModel () Return the metamodel entity corresponding to the root. Return: metamodel entity corresponding to the root Since: JPA 2.0 | |
CriteriaDelete.from(entity) - JPA Method JPA Method in jakarta.persistence.criteria.CriteriaDelete Root from ( EntityType entity ) Create and add a query root corresponding to the entity that is the target of the DELETE. A CriteriaDelete object has a single root, the entity that is being deleted. Parameters: entity | |
CommonAbstractCriteria.subquery(type) - JPA Method JPA Method in jakarta.persistence.criteria.CommonAbstractCriteria Subquery subquery ( EntityType type ) Create a subquery of the query. Parameters: type - the subquery result type Return: subquery Since: JPA 2.1 | |
From | |
From | |
InterfaceRef jakarta.persistence.criteria.CommonAbstractCriteria subquery ( EntityType type) Create a subquery of the query. Parameters: type - the subquery result type Return: subquery Since: JPA 2.1 | |
AbstractQuery | |
Metamodel.entity(entityName) - JPA Method JPA Method in jakarta.persistence.metamodel.Metamodel EntityType entity ( String entityName ) Return the metamodel entity type representing the entity. Parameters: entityName - the name of the represented entity Return: the metamodel entity type Throws: IllegalArgumentException | |
InterfaceRef jakarta.persistence.criteria.Subquery corresponding to the given entity Inherited from: AbstractQuery Since: JPA 2.0 Root from ( EntityType   | |
CriteriaUpdate.from(entity) - JPA Method JPA Method in jakarta.persistence.criteria.CriteriaUpdate Root from ( EntityType entity ) Create and add a query root corresponding to the entity that is the target of the update. A CriteriaUpdate object has a single root, the entity that is being updated. Parameters: entity | |
InterfaceRef jakarta.persistence.criteria.CriteriaQuery from ( EntityType entity) Create and add a query root corresponding to the given entity | |
c.o.jpa.type.EntityTypeImpl.getIdType() returns null hi, i currently try to use objectdb for a new project. i wanted to use it in combination with spring-data-jpa (M2), but i'm not able to use the automatic repository feature because the following code fails EntityType type = metamodel.entity(domainClass);   |