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); // Get an entity type:   EntityType type2 = metamodel. entity (MyEntity.class);   ...  - represents user defined mapped super classes. EntityType  - represents user defined ... = entityType . getSupertype (); // Checks if the type has a single ID attribute: boolean hasSingleId

JPA Interface EntityType Type Parameters: - The represented entity type. Super Interfaces: Bindable , IdentifiableType , ManagedType , Type Instances of the type EntityType represent entity types. Since: JPA 2.0 Public Methods SingularAttribute getDeclaredId (Class  type) Return the attribute

JPA Method in javax.persistence.metamodel. EntityType String getName () Return the entity name. Return: entity name Since: JPA 2.0

(" EntityType : " +e.getName())); : ObjectDB returns with: Exception in thread "main" com.objectdb.o ... -one, Eg: Metamodel m = em.getMetamodel();     EntityType Point_ = m.entity(Point.class);   ... ().getEntities().forEach((e) - System.out.println(" EntityType : " +e.getName())); em.close(); emf.close

  I tried adding an explicit inspection of the EntityType using the metamodel public IMapItem getMapItem(Integer cachedKey, EntityManager em) { Metamodel metamodel = em.getMetamodel(); EntityType

( EntityType  entity) Create and add a query root corresponding to the given entity, forming

2.1 Root from ( EntityType  entity) Create and add a query root corresponding to the entity

JPA Method in javax.persistence.metamodel.Metamodel EntityType entity (   Class  cls ) Return the metamodel entity type representing the entity. Parameters: cls - the type of the represented entity Return: the metamodel entity type Throws: IllegalArgumentException - if not an entity Since: JPA 2.0

JPA Interface Root Type Parameters: - the entity type referenced by the root A root type in the from clause. Query roots always reference entities. Since: JPA 2.0 The FROM clause (JPQL / Criteria API) article explains how to use Root . Public Methods EntityType getModel () Return the metamodel

an embeddable class Since: JPA 2.0 EntityType entity (Class  cls) Return the metamodel entity type

JPA Method in javax.persistence.criteria.Root EntityType getModel () Return the metamodel entity corresponding to the root. Return: metamodel entity corresponding to the root Since: JPA 2.0

JPA Method in javax.persistence.criteria.CriteriaDelete Root from (    EntityType  entity ) Create and add a query root corresponding to the entity that is the target of the delete. A CriteriaDelete object has a single root, the entity that is being deleted. Parameters: entity

JPA Method in javax.persistence.criteria.AbstractQuery Root from (    EntityType  entity ) Create and add a query root corresponding to the given entity, forming a cartesian product with any existing roots. Parameters: entity - metamodel entity representing the entity of type X

( EntityType  entity) Create and add a query root corresponding to the given entity, forming a cartesian

Inherited from: AbstractQuery Since: JPA 2.0 Root from ( EntityType  entity) Create and add

JPA Method in javax.persistence.criteria.CriteriaUpdate Root from (    EntityType  entity ) Create and add a query root corresponding to the entity that is the target of the update. A CriteriaUpdate object has a single root, the entity that is being updated. Parameters: entity

entity Since: JPA 2.1 Root from ( EntityType  entity) Create and add a query root corresponding

hi, i currently try to use objectdb for a new project. i wanted to use it in combination with spring-data-jpa (M2), but i'm not able to use the automatic repository feature because the following code fails      EntityType type = metamodel.entity(domainClass);