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Configure ObjectDB in spring context

="username" value="sa"/> <property name="password" value=""/> </bean> <!--Defining ... /guests.odb"/> <property name="username" value="admin"/> <property name="password

How to enhance the JPA/Spring/MVC to implement RESTfull for CURL client?

= "/user/{username}", method = org.springframework.web.bind.annotation.RequestMethod.GET, headers ... getGuest(@org.springframework.web.bind.annotation.PathVariable String username) { return guestDao

Replication error on slave restart

> <connection port="6136" max="100" /> <data path="$objectdb/db" /> </server> <users> <user username ... > <users>   <user username="xxx1" password="xxx2" admin="true">    <dir path="/" permissions="access

Need disk usage and delete some old files

: File root = com.objectdb.Utilities.getServerFileSystem(     host, port, username, password, false ... .getServerFileSystem(     host, port, username, password, path, false); support Support what about backup

performance limit

/18. This is the query we use select e from AktImpl e where e.createdBy like 'username' Runing this query on 150.000 records gives 126 results in 15 ms for user A. Using this query for username B gives

Activation license not picked up in Jenkins

18.99/1.18 (a.username='a')> <extractPlan 3.7225 18.96/1.18 a(Person ... ] Query "SELECT a FROM common.model.Person a WHERE a.deleted=false AND a.username='dummy_3'" => 0 results

Problem connecting to the replicated server

user. Trianglehead Json Error In the connection url try to specify a username/password for the master server. support Support Hi I have tried that, when I do that it will say "Login Error (bad username

openejb jpa jaas module

<String, Object>(); private String username; private char ... (); try { info = entityManager.find( UserInfo.class , username

JPA-Query does not lead to any result

help us what the problem is? SELECT FROM UserModelData usr WHERE usr.userName = 'admin' Attached ... . skolb Sebastian Kolb The query is executed using an index on field userName. In not-working.odb

order by string with numbers

The sql that works is ORDER BY CAST(SUBSTR(username FROM 4) AS UNSIGNED) ASC Using JPQL SELECT u FROM Users u ORDER BY SUBSTRING(u.username,4)*1 ASC If you have other alternative for JPA

Getting Started

ObjectDB is very easy to use. Follow the Getting Started Tutorial and the Quick Tour manual chapter and in minutes you may be able to write and run first Java programs against ObjectDB.

Prior knowledge or experience in database programming (SQL, JDBC, ORM, JPA, etc.) is not required, but some background in using the Java language is essential.

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