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would a ConcurrentLinkedHashMap). FETCH thread nr (36) count: 982 UIDs in 26 msek FETCH thread nr (41) count: 982 UIDs in 29 msek FETCH thread nr (44) count: 982 UIDs in 14 msek FETCH thread nr (39) count: 982 UIDs in 25 msek FETCH thread nr (42) count: 982 UIDs in 31 msek FETCH

;  System.out.println("COUNT = " + i);     em.close();     try ... ; Point.class);   List<Point> results = query.getResultList();   int count = 0;   for (Point p : results) {    System.out.println(p);    if(count++>5

SELECT count(e) FROM Meta e, ImageNet i, Page p WHERE e.idImage ... ! Each table has about 160K records. What formula can predict the time for such counting? SELECT count(e) FROM Meta

">Aggregates (COUNT, SUM, AVG, MAX, MIN).

) FROM Country c WHERE 'Europe' MEMBER OF c.continents GROUP BY c.currency HAVING COUNT(c) >

">Expression<Long> count_Expression_" title="Method of javax.persistence.criteria.CriteriaBuilder">countcount operation.

"> Create an aggregate expression applying the count distinct operation. - expression representing input value to count distinct operation Returns: count distinct expression

: # Case (1) SELECT COUNT($1) FROM com.lexware ... %'))))) # Case (2) SELECT COUNT($1) FROM com.lexware.vereinsverwaltung.verein.mitglied.Mitglied ... %')))))) # Case (3) SELECT COUNT($1) FROM com.lexware.vereinsverwaltung.verein

;  int Address_1_Count = ((Long) em.createQuery(             "SELECT COUNT(a) FROM Address a WHERE street = '1'")      ... ;    int Address_2_Count = ((Long) em.createQuery(       

> int count = result.size(); Iteration over the result