ObjectDB Database Search

; The database can be branched (and forms a tree with the root at the top and leaves at the bottom); the user selects a leaf to load which is linked up to the root and then the DB is loaded from the root

.class); Root root = query.from(Friendship.class); Path path = root . get("username"); query

;  File root = Utilities.getServerFileSystem(         ... , password, false); This will return the root directory, which then can be explored further using ... root = Utilities.getServerFileSystem(           

detail all the code of generic functions, but a piece of logic is this: private void root (Class type) {   Root root = criteriaQuery.from(type); } private void select(Object object) {  

Given the following: Predicate isOwnedByUser = cb.equal( root .get("owner").get("id"), userId); Predicate ownerIsNull = cb.isNull( root .get("owner")); Predicate ownerMatchesOrIsNull = cb.or(ownerIsNull ... OR o.id = :userId Notice that the navigation  root .get("owner").get("id") is implemented as

the root directory of my web project and now it is being read. So, I think for now I can live with it in 2 locations: project root for development, and WEB-INF/objectdb.conf for deployment. The question

that every Node in my graph is at some level descendant of the root Node. I have been looking for an optimum ... Paul Kant Thanks Erick, I was messing up with the EntityManagers, which was the root of the problem. Have a beautiful day ! paulk Paul Kant

a list of other devices which are also type Device. My root device information are saved properly as ... = interfaceMy;   } } } kiki Kristijan Your code persists only the root object. If you want to cascade

;       Root e = cq.from(A.class);        ... error: private void applyFilters( Root from, CriteriaQuery query, CriteriaBuilder builder) { query

file system root by: File root = com.objectdb.Utilities.getServerFileSystem(     

._PersistenceException: Attempt to begin a new transaction when a transaction is active root cause com.objectdb.o._PersistenceException: Attempt to begin a new transaction when a transaction is active root cause

.criteria. Root ; import java.util.List; import static org.junit.Assert.*; public class LikeTest { @Entity ... (); CriteriaQuery query = builder.createQuery(StringHolder.class); Root c = query.from(StringHolder

How to show in JFXTreeTableView a country like Root with its cities and the city with its communities? I have three classes, Countries, Cities and Communities. The Countries class relates ... the localities. My question?. How to show in JFXTreeTableView a country like Root with its cities and the city

: The replicated databases on the slave server are automatically generated under a special root directory,  $replication , under the server data root directory. Starting a new replication of an existing master

of  SSLSocketImpl and similar classes (in the 3 hprof files). However, trying to find the GC roots ... hprof files). However, trying to find the GC roots that hold these instances (using Java Virtual VM

and of course running garbage collector) 5. the gc root of all those objects is our single ... is, that there are 248 com.objectdb.jdo.PMImpl Objects left, and the root gc is as well the EntityManagerFactory

case, you have 2 distinct tmp directories for the 2 JVMs (if possible, empty the root tmp directory ... that the tmp directory has not been created due to no permission? Can you try running the test with a root user

/persistent-nontransactional   i've checked state of root object, objects are persisted correctly

= criteriaBuilder.createQuery(aClass);      Root entityRoot = q.from(aClass);    

osx menu item (for starting/stopping server, viewing config files, data roots , etc) is extremely useful. However, currently the about box doesn't show the current jar version of the server (and with rapid updates, it's difficult to know which version of the server is currently running, and track

if all the objects are reachable from some root that you load. support Support

Hi, I make a full binary tree of 4095 node, I check the first 9 node, but the root cost 24 seconds, why? Result: =========== find time @ 24.125000 getSons time @ 0.000000 1 : type:Nodes, sons:2 child : 2 child : 3 Iterator time @ 0.000000 find time @ 0.000000 getSons time @ 0.000000 2 : type:Nodes

;    Root cdi = q.from(CDI.class);          

in a libs directory on the root of the eclipse project and then add it to the classpath runtime

and Maven correctly copies META-INF and all contents into the root of jar file when the (EJB) project

. Root ; public final class MyTestCase {     public static void main(String[] args) 

= owner;     }   } } The root cause is: com.objectdb.o.UserException: Attempt

;   CriteriaQuery query1 = cb.createQuery();         Root e

. for example, /usr/local/share/objectdb: lrwxrwxrwx 1 root staff 24 Apr 5 16:44 work - /var/local/objectdb

have a class hierarchy in which both Link and Folder are subclasses of a common root Entry

itself is running in client-server mode using configuration contained in the default location (objectdb root

the path etc. which isn't correct as it was running as root , I just had this suspicious feeling

? Are there additional stack trace lines in the log (the root cause is missing)? support Support

I am getting following error when i am trying to connect to server: [com.objectdb.o._PersistenceException: Login Error (bad username 'admin' or password)] with root cause com.objectdb.o.UserException: Login Error (bad username 'admin' or password) at com.objectdb.o.MSG.d(MSG.java:61) at com

{ CriteriaBuilder cb = em.getCriteriaBuilder(); CriteriaQuery query = cb.createQuery(); Root fromMomentPayload ... ();             Root fromMomentPayload 

.persistence.criteria. Root ; public class T605 {     public static void main(String[] args ... ;       Root e = cq.from(Customer.class);      

us without ordering. The issue is that the name of the root variable is $1 as well as the name ... .criteria. Root ; public final class F329 { public static void main(String[] args) {  

with CriteraBuilder.function("$1.getAge", Integer.class) ($1 is a valid path we've goot from our root selector). NOTE ... goot from our root selector) I cannot create yet another sample as creating samples takes quite some

] with root cause [ObjectDB 2.5.5] Unexpected exception (Error 990) Generated by Java HotSpot(TM ... ] with root cause com.objectdb.o.UserException: Mismatch client-server protocol prefix at com.objectdb

well as paths to these objects from root objects (to see why they are reachable and cannot be garbage ... root objects. Before the flush has been executed, the test persisted 10.000 entities.   btc_es

about the roots and paths that keep these objects in memory (particularly roots and paths

;  private Map data; } Error : Stacktrace:] with root cause com.objectdb.o.UserException

databases. (If you think this is the root of the problem then I can switch it off across the board

to a garbage collection root after stopping is via the hook. Lachezar Lachezar Dobrev Thank

most of these instances (i.e. a path to the root ) may help. support Support Ok, I've uploaded the 3rd heap dump now

of more than one class path root ( issue #554 ). Fixed a NullPointerException on detachment of some objects. Fixed Linux "Name or service not known" error on server stop.

to put a test together but we're taking a slightly different root at the application level to work

Hi, I am doing something simple like final Root from = criteria.from(T.class) final Path path = from.get("someStringProperty") final Expression upperPath = builder.upper((Expression ) path); upperPath.alias("TEST"); criteria.multiselect(from, path); criteria.orderBy(builder.asc(upperPath)) I

From my Entities a StaticMetamodel is generated through Hibernate JPA 2 Metamodel Generator. When i now try to build a query with the Specification-Interface [new Specification () {     @Override public Predicate toPredicate(final Root benutzerRoot, final CriteriaQuery

{ private String message; public Thing(String mess) { message = mess; } } package.jdo (in the root