8 | Query problem after transaction commit Attached please find the test code. The screen output is at the end of the post. Please help. Thx ... successfully] 04> SELECT u FROM Goods u where u._code like :code AND u._desc like :desc 05> code= %, desc= % 06> UI: end query 07> UI: start printing result 08> code= A, desc= Good A, byUser= test 09> code |
1 | Literals in JPQL and Criteria Queries. Country). That is equivalent to Country.class in Java code. Notice that the name of the entity class |
1 | Running JPA Queries of a single object is easy and the code is simple: Query query = em.createQuery("SELECT COUNT(c) FROM |
0 | Step 4: Add a Servlet Class servlet class. Now replace the content of the new source file with the following code: package guest |
0 | Step 4: Add a Servlet Class servlet class. Now replace the content of the new source file with the following code: package guest |
0 | Step 3: Define an EJB Session Bean code: package guest; import java.util.List; import javax.ejb.Stateless; import javax |
0 | Step 4: Add a Controller Class replace the content of the new source file with the following code: package guest; import javax |
0 | Step 2: Entity Class and Persistence Unit content with the following code: package guest; import java.io.Serializable; import java.sql |
0 | Step 3: Define a Spring DAO Component source file with the following code: package guest; import java.util.List; import javax |
0 | Step 2: Define a JPA Entity Class and paste to replace the new source file content with the following code: package guest; import java.io |
